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118=x^2-3
We move all terms to the left:
118-(x^2-3)=0
We get rid of parentheses
-x^2+3+118=0
We add all the numbers together, and all the variables
-1x^2+121=0
a = -1; b = 0; c = +121;
Δ = b2-4ac
Δ = 02-4·(-1)·121
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22}{2*-1}=\frac{22}{-2} =-11 $
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